Question

How do I rewrite the following polar equation as an equivalent Cartesian equation: r=5/(sin(theta)-2cos(theta)) ?

Answer 1

`y=2x+5`

Explanation:

`r=5/(sin(theta)-2cos(theta))`

`r(sin(theta)-2cos(theta))=5`

`rsin(theta)-2rcos(theta)=5`

Now we use the following equations:
`x=rcostheta`
`y=rsintheta`

To get:
`y-2x=5`

`y=2x+5`