# How do I solve 3 sin x+2 tan x=0 for 0°<x<360° ?

$\sin x \left[3 + 2 \sec x\right]$ = $0$ $\implies$ $\sin x$ = $0$ or $\sec x = - \frac{3}{2}$ $\implies$
$x$ = 180° or $x$ = ${\sec}^{-} 1 \left(- \frac{3}{2}\right)$
The angle ${\sec}^{-} 1$ $\left(- \frac{3}{2}\right)$ can be got from four figure tables.