How do I solve...? sinx=√3-sinx

1 Answer
Feb 20, 2018

See below.

Explanation:

#sinx=sqrt(3)-sinx#

Add #sinx# to both sides:

#sinx+sinx=sqrt(3)-sinx+sinx#

#2sinx=sqrt(3)#

Divide both sides by #2#:

#sinx=sqrt(3)/2#

#x=arcsin(sinx)=arcsin(sqrt(3)/2)=>x=pi/3+2pik,(2pi)/3+2pik#

#x=arcsin(sinx)=arcsin(-sqrt(3)/2)=>x=-pi/3+2pik,-(2pi)/3+2pik#

For any integer #k#