Question

How do i solve this using the Quadratic Formula? `2x^2 + 3x - 6 = 0`

Answer 1

`x = -3/4 +- sqrt(57)/4`

Explanation:

Given: `2x^2 + 3x - 6 = 0`

The quadratic formula: `x = (-B +- sqrt(B^2 - 4AC))/(2A)`, where the equation is in general form: `Ax^2 + Bx + C = 0`

`A = 2; " "B= 3; " "C = -6`

`x = (-3 +- sqrt(3^2 - 4*2*(-6)))/(2*2) = -3/4 +- sqrt(57)/4`

Since `sqrt(57) = sqrt(3)sqrt(19)` which can't be simplified, we leave it as `sqrt(57)`