Question

How do I use the vertex formula to determine the vertex of the graph for `y=x^2+4x+1`?

Answer 1

Vertex form of quadratic:
`x=m(x-a)^2+b`
with vertex `(a,b)`

`y=x^2+4x+1`

`y=(x^2+4x+4) -4 +1`

`y=(x-(-2)) +(-3)`

Vertex is at `(-2,-3)`