How do solve the following linear system?: # x-4y=2 , x-7y=4 #? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Sara Dec 28, 2015 #(-2/3,-2/3)# Explanation: Try to leave #x# alone in one side of the equation, then equate the other sides; #x=2+4y , x=4+7y# #2+4y=4+7y# #-># #-3y=2# #y=-2/3# Now, write #-2/3# instead of #y# in one of the equations, the value of #x# will be the same for both of them. #x=2+4.(-2/3)# #-># #x=2-8/3# #x=-2/3# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1483 views around the world You can reuse this answer Creative Commons License