How do you simplify #(4x^5)/(16x^3)#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer George C. Jul 11, 2015 #(4x^5)/(16x^3) = (4x^3*x^2)/(4x^3*4) = x^2/4# with exclusion #x != 0# Explanation: Use #x^(a+b) = x^a*x^b# Note that if #x = 0# then #(4x^5)/(16x^3) = 0/0# has undefined value. Hence the exclusion. Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1754 views around the world You can reuse this answer Creative Commons License