How do you add #(-3+i) + (4+6i)#? Precalculus Complex Numbers in Trigonometric Form Complex Number Plane 1 Answer F. Javier B. Mar 29, 2018 #1+7i#. See explanation below Explanation: The addition in #CC# is defined by #(a+bi)+(c+di)=(a+c)+(b+d)i#. The two complex numbers addition consists in adding real parts and imaginary parts separately. In our case #(-3+i)+(4+6i)=(-3+4)+(1+6)i# because the imaginary part of first complex number is 1. Then we have: #(-3+4)+(1+6)i=1+7i# Answer link Related questions What is the complex number plane? Which vectors define the complex number plane? What is the modulus of a complex number? How do I graph the complex number #3+4i# in the complex plane? How do I graph the complex number #2-3i# in the complex plane? How do I graph the complex number #-4+2i# in the complex plane? How do I graph the number 3 in the complex number plane? How do I graph the number #4i# in the complex number plane? How do I use graphing in the complex plane to add #2+4i# and #5+3i#? How do I use graphing in the complex plane to subtract #3+4i# from #-2+2i#? See all questions in Complex Number Plane Impact of this question 1795 views around the world You can reuse this answer Creative Commons License