How do you add $(-3+i) + (4+6i)$ ?

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Answer 1 · 2018-03-29T11:49:14

$1+7i$ . See explanation below

The addition in $CC$ is defined by

$(a+bi)+(c+di)=(a+c)+(b+d)i$ . The two complex numbers addition consists in adding real parts and imaginary parts separately.

In our case

$(-3+i)+(4+6i)=(-3+4)+(1+6)i$ because the imaginary part of first complex number is 1. Then we have:

$(-3+4)+(1+6)i=1+7i$

How do you add (-3+i) + (4+6i)(-3+i) + (4+6i)?