Question

How do you add `(3y)/(2y^2-y)+4/y`?

Answer 1

`=(11y-4)/(y(2y-1))`

Explanation:

`(3y)/(2y^2-y)+4/y`
`=(3y)/(y(2y-1))+4/y`
`=(3y+8y-4)/(y(2y-1))`
`=(11y-4)/(y(2y-1))`