Question

How do you add `(6-i)` and `(-7+2i)` in trigonometric form?

Answer 1

`(6-i)+(-7+2i)=`

Explanation:

First we add algebraically
`(6-i)+(-7+2i)=(6-7)+(-1+2)i=-1+i=sqrt((-1)^2+1^2)[cos(arctan(1/-1))+isin(arctan(1/-1))]`

`=sqrt2[cos(arctan(1/-1))+isin(arctan(1/-1))]`

God bless....I hope the explanation is useful.