Question

How do you add `\frac { 3r } { 5x ^ { 2} y } + \frac { 4s } { 3x y ^ { 2} }`?

Answer 1

multiply each fraction by what is needed to give a common denominator.

Explanation:

The common denominator is `15x^2y^2`

multiply the first fraction by `(3y)/(3y)` remember this fraction must equal 1 so as not to change the value.

multiply the 2nd fraction by `(5x)/(5x)`

the problem is then

#[(3y)/(3y)][(3r)/(5x^2y)] + [(5x)/(5x)][(4s)/(3xy^2)]=(9ry)/ (15x^2y^2)+(20sx)/(15x^2y^2)=(9ry+20sx)/(15x^2y^2)#