# How do you answer this?

##### 2 Answers

#### Answer:

#### Explanation:

Using complete the square:

Half term of

Put inside bracket and square it, adding on the constant.

Take away the squared number of the term of

Collect like terms

This is the completed the square format, but now we solve.

Add

Get rid of the squared bracket, by square rooting

Remember the

Add 4

This means the answer will be either

#### Answer:

#### Explanation:

#"solve using the method of "color(blue)"completing the square"#

#x^2-8x-3=0#

#• " the coefficient of the "x^2" term must be 1 which it is"#

#• " add/subtract "(1/2"coefficient of the x-term")^2" to"#

#x^2-8x#

#x^2+2(-4)xcolor(red)(+16)color(red)(-16)-3=0#

#rArr(x-4)^2-19=0#

#rArr(x-4)^2=19#

#color(blue)"take the square root of both sides"#

#sqrt((x-4)^2)=+-sqrt19larrcolor(blue)"note plus or minus"#

#rArrx-4=+-sqrt19#

#"add 4 to both sides"#

#rArrx=4+-sqrt19larrcolor(red)"exact values"#