# How do you balance Ag_2O -> Ag + O_2?

Jan 16, 2016

$2 A {g}_{2} O \rightarrow 4 A g + {O}_{2}$

#### Explanation:

Balancing a chemical equation consists of changing the coefficient of molecules in order to make the number of atoms equal on both side.

Consider the given equation:

$A {g}_{2} O \rightarrow A g + {O}_{2}$

Notice how there is only one $O$ on the reactants side, but two on the products side. This can be fixed by multiplying the reactant by $2$.

$\textcolor{red}{2} A {g}_{2} O \rightarrow A g + {O}_{2}$

Now that the oxygen atoms are balanced, all that remains is the silver. There are now four $A g$ on the reactant side and only one on the product side, which can be remedied with a coefficient of four on the products side.

$2 A {g}_{2} O \rightarrow \textcolor{b l u e}{4} A g + {O}_{2}$

This is completely balanced.