# How do you balance NH_4OH + FeCl_3 -> Fe(OH)_3 + NH_4Cl?

In LHS you have 3 Cl, to balance you are to take 3 before $N {H}_{4} C l$ in RHS, Now you are to write 3 before $N {H}_{4} O H$in LHS and it will be balanced
$3 N {H}_{4} O H + F e C {l}_{3} = F e {\left(O H\right)}_{3} + 3 N {H}_{4} C l$