How do you balance the equation C4H10+O2 = CO2+H2O?
We have the unbalanced equation:
This is the combustion of butane,
Let's first balance the carbons. There are four on the
Now, let's balance the hydrogens. There are
Final step is to balance the oxygens. There are two on the left hand side, but thirteen on the right hand side, so we need to divide thirteen by two to get the "scale number", which is
But wait, we cannot have half a molecule! So, we need to multiply the whole equation by
The given equation to be balanced is
We begin by counting the number of
Now count the number of
Lets verify, by counting the number of each atom on each side.
Hence the equation is balanced :)
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