# How do you balance this equation? MnO_2 + Al -> Mn + Al_2O_3

Jul 7, 2016

$3 M n {O}_{2} + 4 A l \to 3 M n + 2 A {l}_{2} {O}_{3}$

#### Explanation:

Since we have a multiple of $3$ oxygens on the right hand side we require a multiplier of $3$ on the left hand side.

If we have $3 M n {O}_{2}$ on the left hand side, then that is a total of $3$ manganeses and $6$ oxygens, requiring $3 M n + 2 A {l}_{2} {O}_{3}$ on the right hand side.

Then we need $4$ aluminiums on the left hand side.

Hence the balanced form of the equation is:

$3 M n {O}_{2} + 4 A l \to 3 M n + 2 A {l}_{2} {O}_{3}$