Question

How do you balance this equation: Na+ [HCO3]- + CH3-COOH --> CH3-COO- Na+ H20 + CO2 ?

Answer 1

Have you not done it already....?

Explanation:

You gots an acid-base reaction in which sodium bicarbonate reacts with acetic acid to give sodium acetate, and carbon dioxide, and water....

`underbrace(Na^+HCO_3^(-) +H_3C-CO_2H)_(144.01* g)stackrel("acid base reaction")rarr`

`underbrace(H_3C-CO_2^(-)Na^+ + CO_2(g)uarr+H_2O(l))_(144.01*g)`

Charge is balanced, and MASS is balanced...as is the stoichiometric requirement....