Question

How do you calculate `Arccos (sin (pi/6))`?

Answer 1

Find `arccos(sin (pi/6))`

Ans: `+- pi/3`

Explanation:

`sin (pi/6) = 1/2`
therefor `arccos (sin(pi/6)) = arccos (1/2)`
On the trig unit circle,

`cos x = 1/2` --> arc `x = +- pi/3`