# How do you find the vertex of #f(x)=(x-1)^2-1#?

##### 1 Answer

May 7, 2018

#### Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#

#"where "(h,k)" are the coordinates of the vertex and a"#

#"is a multiplier"#

#f(x)=(x-1)^2-1" is in vertex form"#

#"with "h=1" and "k=-1#

#rArrcolor(magenta)"vertex "=(1,-1)#

graph{(y-x^2+2x)=0 [-10, 10, -5, 5]}