How do you calculate the distance above the surface of the earth to geosynchronous orbit?
The height of a geostationary orbit is calculated as the distance required to have an orbital period of 24 hours.
The force of gravity acting on a satellite is given by the formula
The centripetal force required to keep the satellite in orbit is given by the formula
#F=m * r * omega^2#.
#omega = (2pi)/(24*60*60)#
is the angular velocity of the satellite in radians per second. The value of
When a satellite is in orbit the gravitational force must equal the centripetal force which gives the formula
The distance is from the centre of the Earth so we need to subtract the radius of the Earth
So the height of geostationary orbit h is given by the formula:
#h=((GM)/(omega^2))^(1/3) - R#
If the stated values of G, M,