How do you calculate the mean, median, and mode of 7, 3, 2, 1, 13, 8, 1, 5, 14, 11, 15?

May 10, 2018

Below

Explanation:

Mean: the average of your numbers ie sum of your numbers divided by the number of your numbers
SO: $\frac{7 + 3 + 2 + 1 + 13 + 8 + 1 + 5 + 14 + 11 + 15}{11} = \frac{80}{11} = 7.27$

Median: the middle value of all your numbers when placed in ascending order
SO: $1 , 1 , 2 , 3 , 5 , 7 , 8 , 11 , 13 , 14 , 15$
Since there are 11 numbers, your median will be your 6th number which is 7

Mode: the number that occurs the most
SO: from above when the numbers are ordered in ascending order, you'll noticed that 1 occurs twice. Hence, your mode is 1

May 10, 2018

By arranging the series

Explanation:

Order your results (from the lowest observation the to greatest):

$1 , 1 , 2 , 3 , 5 , 7 , 8 , 11 , 13 , 14 , 15$

The mean is $A v e = \frac{1 + 1 + 2 + 3 + 5 + 7 + 8 + 11 + 13 + 14 + 15}{11}$

$A v e = \frac{80}{11} = 7.28$

The median is 7 (it disects the set - it is the 6th number).

The mode is 1 (there are two 1s repeated). Only one mode exists in this series.