# How do you calculate the molarity of a solution prepared by dissolving 95.5 grams of KNO_3 in enough water to make 750 mL of solution?

$\text{Molarity"="Moles of solute"/"Volume of solution}$
$\text{Molarity} = \frac{95.5 \cdot g}{101.10 \cdot g \cdot m o {l}^{-} 1} \times \frac{1}{750 \times {10}^{-} 3 L}$ $=$
??*mol*L^-1