# How do you calculate the tan(sin^-1(0))?

Nov 21, 2015

$0$

#### Explanation:

A way to interpret this is to ask yourself the following:

When $\sin x = 0$, what's $\tan x$?

$\sin x = 0$ at $0 , \pi$.

However, you must know the domain of the function ${\sin}^{-} 1 \left(x\right)$ is $- \frac{\pi}{2} < x < \frac{\pi}{2}$, so only $0$ applies.

Now, we know that ${\sin}^{-} 1 \left(0\right)$ is $0$, so we evaluate $\tan 0$ to once again receive an answer of $0$.