How do you compare the graph of p(x) = 1/3x to the graph of f(x) = x?
1 Answer
Mar 3, 2017
Vertical Compression/Horizontal Stretch by a factor of 3.
Explanation:
Original Graph: (y = x)
graph{y = x}
Modified Graph: (y = 1/3x)
graph{y = 1/3x [-10, 10, -5, 5]}
From these two graphs you notice that there is a vertical compression (in the same manner, a horizontal stretch) according to transformations regarding the equation:
Because a vertical compression/horizontal stretch involves p(x) being modified by "a" factor between 0 and 1 (ie 1/3):
In universal terms:
#g(x) = af(x)# Assuming (in this case)
#f(x) = x or p(x) = f(x)#
and# a = 1/3# In even simpler simpler terms, every y point is equal to
#1/3x#
So if#x = 1# then#y = 1/3#
