How do you complete the equation of the line through (-1, 6) and (7, -2)?

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Answer 1 · 2017-09-02T23:14:40

# y= -x+5#

#(-1, 6) and (7, -2) -> "slope" = m = (y_2-y_1)/(x_2-x_1)#

So

#m = (-2-6)/(7- (-1)) = (-8)/8= -1#

Use

#y=mx+c#

Plug in #(x,y) = (-1,6)#

#6=-1 xx (-1) + c#

#6= 1 + c#

#c=5#

#:. y= -x+5#

-Fish