How do you complete the ordered pair (-6, ?) given 2/3x + y - 1 = 0?

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Answer 1 · 2016-04-28T12:26:06

So #(-6,?)->(-6,+5)#

Given:#" "(x,y)->(-6,?)#
#2/3 x+y-1=0#

Thus the unknown value is that of #y# and the known value is that of #x#.

By substitution for #x=-6#

#2/3 x+y-1=0" "->" "2/3(-6)+y-1=0#

#-4+y-1=0#

#-5+y=0#

Add 5 to both sides

#+5-5+y=0+5#

But # 5-5=0#

#y=+5#

So #(-6,?)->(-6,+5)#