# How do you complete the square f(x)=x^2+6x-3?

Nov 18, 2016

$f \left(x\right) = 1 \left({x}^{2} + 6 x + m - m\right) - 3$

$m = {\left(\frac{b}{2}\right)}^{2} = {\left(\frac{6}{2}\right)}^{2} = 9$

$f \left(x\right) = 1 \left({x}^{2} + 6 x + 9 - 9\right) - 3$

$f \left(x\right) = 1 {\left(x + 3\right)}^{2} - 9 - 3$

$f \left(x\right) = {\left(x + 3\right)}^{2} - 12$

Hopefully this helps!