# How do you complete the square to find the vertex for y + 6 = x^2 - 5x?

Jun 7, 2015

$y + 6 = {x}^{2} - 5 x$

$y = {x}^{2} - 5 x - 6$

$y = {x}^{2} - 5 x + \textcolor{b l u e}{\frac{25}{4}} - 6 - \textcolor{b l u e}{\frac{25}{4}}$

$y = {\left(x - \frac{5}{2}\right)}^{2} - \frac{24 + 25}{4}$

$y = {\left(x - \frac{5}{2}\right)}^{2} - \frac{49}{4}$

Vertex: $\left(\frac{5}{2} , - \frac{49}{4}\right)$