Question

How do you condense `1/3[lnx^9 - lny^12]`?

Answer 1

`[ln(x^9/y^12)]^(1/3)`

Explanation:

Use the Property: `log_b (x/y)=log_bx-log_by and log_bx^n=nlog_bx`

`1/3 [ln(x^9/y^12)]`

`[ln(x^9/y^12)]^(1/3)`