How do you convert (-2,-14pi/5) to rectangular coordinates? I'm struggling

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Answer 1 · 2018-04-19T14:54:26

#color(blue)(( 1.62 , 1.18 )#

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It can be seen from the diagram that the x coordinate of P is #rcos(theta)# and the y coordinate of P is #rsin(theta)#

So:

Cartesian coordinates will be #(rcos(theta),rsin(theta))#

#x=rcos(theta)#

#y=rsin(theta)#

From example:

#x=-2cos((-14pi)/5)=1.62# (2 .d.p.)

#y=-2sin((-14pi)/5)=1.18# (2 .d.p.)

Cartesian coordinate:

#( 1.62 , 1.18 )#