How do you convert 2+(sqrt 3)i to polar form?

The polar coordinates are: $P \left(\sqrt{7} , .714\right)$
$r = \sqrt{{2}^{2} + {\left(\sqrt{3}\right)}^{2}} = \sqrt{4 + 3} = \sqrt{7}$
Calculate the angle $\theta$:
$\theta = {\tan}^{-} 1 \left(\frac{\sqrt{3}}{2}\right) = {40.89}^{0} = .714 \text{ radians}$
The polar coordinates are: $P \left(\sqrt{7} , .714\right)$