# How do you convert -3-3i to polar form?

In polar form the equation is $Z = 3 \sqrt{2} \left(\cos 225 + i \sin 225\right)$
Let Z= -3 -3i ; Modulas $Z : r = \sqrt{{\left(- 3\right)}^{2} + {\left(- 3\right)}^{2}} = 3 \sqrt{2}$
Argument Z; theta = 180^0 + tan^-1(3/3) = 180+45=225^0 (180^0 added as the point lies in 3rd quadrant). In polar form the equation is $Z = 3 \sqrt{2} \left(\cos 225 + i \sin 225\right)$[Ans]