How do you convert 3=(7x-5y)^2-y into polar form?

1 Answer
Apr 23, 2018

Put x=rcostheta and y=rsintheta

Explanation:

3=(7x-5y)^2 - y ...............(Given equation)

Put x=rcostheta and y=rsintheta ; we get :-

rArr3=(7rcostheta-5rsintheta)^2-rsintheta

rArr3=49r^2cos^2theta+25r^2sin^2theta-70r^2costheta.sintheta-rsintheta

rArr3=24r^2cos^2theta+(25r^2cos^2theta+25r^2sin^2theta)-70r^2costheta.sintheta-rsintheta

rArr3=24r^2cos^2theta+25r^2-70r^2costheta.sintheta-rsintheta

:.25r^2+24r^2cos^2theta-70r^2costheta.sintheta-rsintheta-3=0

is the Polar form