Question

How do you convert 64.3 grams of `Al_2(CO_3)_3` to moles?

Answer 1

`"Moles"` `=` `"Mass of stuff"/"Molar mass of stuff"`

Explanation:

So `(64.3*cancelg)/(233.99*cancelg*mol^-1)` `~=` `0.25` `mol`.