# How do you convert  x=y²-6y+11  into polar form?

Sep 12, 2017

see below

#### Explanation:

Use the formulas $x = r \cos \theta , y = r \sin \theta$ to substitute into the equation.

That is,

$x = {y}^{2} - 6 y + 11$

$r \cos \theta = {r}^{2} {\sin}^{2} \theta - 6 r \sin \theta + 11$

$0 = {r}^{2} {\sin}^{2} \theta - 6 r \sin \theta - r \cos \theta + 11$