Question

How do you determine if `y=x^3+1` is an even or odd function?

Answer 1

y is neither odd nor even.

Explanation:

`y(-x) = y(x)`, for even functions and `y(-x) =- y(x)`, for odd functions.
Here, `y(x)=x^3+1 and y(-x) = -x^3+1`.