Question

How do you determine ordered pairs are part of the solution set of inequalities ex: `3x+y<=6` for (4,3),(-2,4),(-5,-3),(3,-3)?

Answer 1

Assuming I understand the question; you need to know which of the pairs `(4,3), (-2,4),(-5,-3),` and `(3,-3)`
satisfy the inequality
`3x+y <= 6`

For each pair
substitute their values for `x` and `y`
in the expression `3x+y`
and select only those that evaluate as `<=6`

For (4,3)
`3(4)+3 =15`
which is not `<= 6` and is therefore not part of the solution set.

Continue with the other 3 possible pairs.