How do you determine ordered pairs are part of the solution set of inequalities ex: #3x+y<=6# for (4,3),(-2,4),(-5,-3),(3,-3)?

1 Answer
Apr 3, 2015

Assuming I understand the question; you need to know which of the pairs #(4,3), (-2,4),(-5,-3),# and #(3,-3)#
satisfy the inequality
#3x+y <= 6#

For each pair
substitute their values for #x# and #y#
in the expression #3x+y#
and select only those that evaluate as #<=6#

For (4,3)
#3(4)+3 =15#
which is not #<= 6# and is therefore not part of the solution set.

Continue with the other 3 possible pairs.