How do you determine the Amplitude, period and phase shift for #y = 1/2 sin(x + pi)#?

1 Answer
Jim H
Jul 1, 2015

#y=asin(bx+c)#

Explanation:

Has
Amplitude = #absa#, in this case Amplitude = #1/2#

Period = #(2pi)/b#, in this case Period = #(2pi)/1 = 2pi#

You can learn a formula for Phase Shift, but I never use one. To find the phase shift, solve #bx+c=0#

In this case #x+pi = 0# at #x=-pi#, so Phase Shift = #-pi#

Related questions
See all questions in Amplitude, Period and Frequency
Impact of this question
1709 views around the world
You can reuse this answer
Creative Commons License