How do you determine the interval(s) on which the function #y= ln(x) / x^3# is concave up and concave down?

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Answer 1 · 2015-04-15T15:04:58

Have a look:
enter image source here
Graphically:
graph{(ln(x))/x^3 [-5.55, 5.547, -2.774, 2.77]}