# How do you determine the limit of 1/(x-4) as x approaches 4^-?

${\lim}_{x \to {4}^{-}} \left(\frac{1}{x - 4}\right) = - \infty$
$x \to {4}^{-}$ so $x - 4 < 0$
${\lim}_{x \to {4}^{-}} \left(\frac{1}{x - 4}\right) {=}^{\left(\frac{1}{0} ^ \left(-\right)\right)} - \infty$