Question

How do you determine the min and max of `x^2 + 2x - 8`?

Answer 1

Find Min of y = x^2 + 2x - 8

Explanation:

Since a > 0, the parabola opens upward, there is a minimum at the vertex.
x-coordinate of vertex: `x = (-b/2a) = -2/2 = - 1`
y-coordinate of vertex: `y = f(-1) = 1 - 2 - 8 = - 9`