Question

How do you determine the number of possible solutions, if any, using the rule for law of sines(ambiguous case) given A=30, a=3, b=8?

Answer 1

`sinB= (bsinA)/a = (8sin30^@)/3` so we get:

`sinB = (8*(1/2))/3 =4/3`

Which is not possible so there is no solution.

With `A=30^@` and `b=8` the minimum for side `a` would be `4` (with `B= 90^@`).