Question

How do you determine the value of 4 so that (6,4), (9,2) has slope 1/3?

Answer 1

For the line to have a slope of `1/3`, `4` should take the value `1`

Explanation:

The slope of a straight line is `m=1/3`

The line connecting points `(6,4);(9,2)` cannot have the slope `1/3`

The option open to us is to change the value of `4` in the point `(6,4)`

Let us assume instead of `4`, we supply value `n`

Then that point is `(6,n)`.

The line connecting points `(6,n); (9,2)` has a slope of `1/3`

We have to find the value of `n`

`m=(y_2-y_1)/(x_2-x_1)`
`(y_2-y_1)/(x_2-x_1)=1/3`

`x_1=6`
`y_1=n`
`x_2=9`
`y_2=2`

`(2-n)/(9-6)=1/3`
`(2-n)/3=1/3`
`2-n=1/3xx3=1`
`-n=1-2=-1`
`n=1`

For the line to have a slope of `1/3`, `4` should take the value `1`