Question

How do you determine the Vertex as an ordered pair when `f(x)=3(x+2)^2-1`?

Answer 1

`(–2, –1)`

Explanation:

The vertex can be found when `f(x)` is minimised. This is the case when `(x+2)^2=0 => x=–2`. Since `(x+2)^2=0` when `x=–2`, `f(–2) = –1`.

Thus the vertex is `(–2, –1)`