# How do you determine the Vertex as an ordered pair when f(x)=3(x+2)^2-1?

(–2, –1)
The vertex can be found when $f \left(x\right)$ is minimised. This is the case when (x+2)^2=0 => x=–2. Since ${\left(x + 2\right)}^{2} = 0$ when x=–2, f(–2) = –1.
Thus the vertex is (–2, –1)