# How do you determine whether the graph of y=sqrt(2-x^2) is symmetric with respect to the x, y axis?

Nov 28, 2016

See explanation

#### Explanation:

Square both sides giving

${y}^{2} = 2 - {x}^{2}$

${x}^{2} + {y}^{2} = 2$

This is the equation of a circle centred at the origin

Thus is symmetrical about both the x and y axis
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Note that the question does NOT use the format $y = \pm \sqrt{2 - {x}^{2}}$