Question

How do you differentiate `e^(2x^2-4x)` using the chain rule?

Answer 1

`=4(e^(2x^2-4x))(x-1)`

Explanation:

`d/(dx)(e^(2x^2-4x))=(e^(2x^2-4x))d/(dx)(2x^2-4x)`
`=(e^(2x^2-4x))(d/(dx)(2x^2)-d/(dx)(4x))`
`=(e^(2x^2-4x))(2*2x^(2-1)-4))`
`=(e^(2x^2-4x))(4x-4)`
`=4(e^(2x^2-4x))(x-1)`