Question

How do you differentiate `f(t)=sin^2(e^(sin^2t))` using the chain rule?

Answer 1

`2sine^[sin^2t]` `cose^[sin^2t]`

Explanation:

`sin^2[e^[sin^2t]]= [sine^[Sin^2t]]^2` so using the chain rule , we have ....

`2[sine^[sin^2t]]` times the differential within the the brackets ie......

`cos[e^[sin^2t]]` and so we get d/dt`=2sine^[sin^2t]` `cose^[sin^2t]`.