How do you differentiate #f(x) = (1-3sqrt(2x^2-1))^2 # using the chain rule? Calculus Basic Differentiation Rules Chain Rule 1 Answer Bdub Nov 1, 2016 #f'(x)=(-12x(1-3sqrt(2x^2-1)))/sqrt(2x^2-1)# Explanation: #f(x)=(1-3sqrt(2x^2-1))^2# #f'(x)=2(1-3sqrt(2x^2-1)) (-3)/(2sqrt(2x^2-1)) *4x # #f'(x)=(-12x(1-3sqrt(2x^2-1)))/sqrt(2x^2-1)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1207 views around the world You can reuse this answer Creative Commons License