# How do you differentiate f(x)=1-(3x-3)^2 using the chain rule.?

Jul 18, 2017

$f \left(x\right) = 1 - {\left(3 x - 3\right)}^{2}$
$f ' \left(x\right) = - 2 \left(3 x - 3\right) \cdot \left(3 x - 3\right) ' = - 2 \left(3 x - 3\right) \cdot 3 =$
$- 6 \left(3 x - 3\right)$