Question

How do you differentiate `f(x)=((1/x)^2-x)` using the chain rule?

Answer 1

`f'(x) = -2/x-1`

Explanation:

`f(x) =( (1/x)^2 -x)`

`= x^-2 -x`

NB: Although the question calls for use of the chain rule, this is not applicable in this case. The derivative may be found by applying the power rule.

`f'(x) = -2x^-1 -1`

`= -2/x-1`